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Mathematics 17 Online
OpenStudy (anonymous):

when we say a varies inversely with b...

OpenStudy (anonymous):

|dw:1361065904836:dw|

OpenStudy (agent0smith):

It means that as b increases, a decreases, and vice-versa.

OpenStudy (anonymous):

how would I write that symbol in latex?

OpenStudy (agent0smith):

\[a \alpha \frac{ 1 }{ b }\]

OpenStudy (agent0smith):

The alpha symbol is a bit close to the a, but it's about the best I could do.

OpenStudy (kropot72):

You can write it as \[a=\frac{k}{b}\] where k is a constant of proportionality.

OpenStudy (anonymous):

so this statement: The electrostatic force varies inversely with the square of their separation distance means: \[F \;\;\;\alpha \;\;\;\;r^2\] correct?

OpenStudy (agent0smith):

No, that's directly proportional. Needs to be 1/r^2

OpenStudy (unklerhaukus):

``` \proto ``` \[\propto\]

OpenStudy (agent0smith):

@UnkleRhaukus looks like it's propto not proto \[F \propto \frac{ 1 }{r^2 }\]

OpenStudy (unklerhaukus):

* ``` \propto ``` \[\propto\]

OpenStudy (anonymous):

Makes sense. Thanks everyone!

OpenStudy (unklerhaukus):

The electrostatic force varies inversely with the square of their separation distance\[\mathbf{\vec F}\propto \frac1{r^2}\quad\implies\quad\mathbf{\vec F}= \frac k {r^2}\]

OpenStudy (agent0smith):

btw \[F \;\;\;\alpha \;\;\;\;r^2 \] would mean that the electrostatic force varies directly with the square of the distance, ie as the distance increases, force increases - which we know is not true.

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