Anybody explain me, please
whats 2 plus 2
iam not done yet
\(\vec a\) =(-3,2,sqr3), find the unit vector that has the same direction as the given vector. I have (\[\frac{ -3 }{4 },\frac{ 1 }{ 2 },\frac{ \sqrt{3} }{4 }\]
dang ur smart
or wat
but according to the definition, sum of components of unit vector must be =1, I don't get it even mine is the same with the answer in book, please explain me what is wrong
Sum of the components SQUARED will equal 1.
@pepsa I am really need explanation from people who know about the field. please, don't have fun with my problem
You can't just add the components together - you need to square each one first if you're looking for the magnitude of the vector.
Square each of these and add them together\[\frac{ -3 }{4 },\frac{ 1 }{ 2 },\frac{ \sqrt{3} }{4 }\]
yes, i got it if do as you guide. so, it means i have to square them first?
thanks a lot, I got it now. since the length of the unit vector means I must do as you guide.
|dw:1361068640135:dw| eg. \[\left( \frac{ 1 }{\sqrt 2 } \right) ^2+ \left( \frac{ 1 }{\sqrt 2 } \right) ^2 = 1\] If you just add 1/sqrt 2 +1/sqrt2, that won't equal 1.
yes, pythagorean theorem
Yep, that's how the length of a vector is found. ~same thing applies in 3D.
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