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Chemistry 22 Online
OpenStudy (anonymous):

what mass of sodium chloride is produced when chlorine reacts with 0.29 g of sodium iodide

OpenStudy (anonymous):

what have you got as your reaction equation?

OpenStudy (anonymous):

\[2NaI+Cl2\rightarrow2NaCl+I2\]

OpenStudy (anonymous):

Is it in this way?

OpenStudy (anonymous):

if it's right then: Na=23 I=127 0.29/(127+23)= how many mole of NaI we've got, which = the mole of NaCl

OpenStudy (anonymous):

then : ?mole x (23+35)= the mass of NaCl you get

OpenStudy (abb0t):

That's correct. Once you have your balanced equation, use dimensional analysis to convert from grams NaI -> mols NaI -> mols NaCl -> grams of NaCl

OpenStudy (anonymous):

Hi thanks everybody - HOW DO YOU GET A BALANCED EQUATION!?

OpenStudy (anonymous):

it counts on a bit of experience, take this one for example, I haven't met this equation before , but I inferred from your posting

OpenStudy (anonymous):

you have to find out the elements and compounds of the equation

OpenStudy (anonymous):

in this case, the question says Cl2 reacts with NaI and it also says we get NaCl after reacting

OpenStudy (anonymous):

then, what's left? It's "I" and I always exists in this way : I2 so we got the equation

OpenStudy (anonymous):

then we gonna balance it, this is a simple case, you can find more examples to practice in this case i' post pic

OpenStudy (anonymous):

OpenStudy (anonymous):

@chemistrybites here

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