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Chemistry 9 Online
OpenStudy (anonymous):

plzzz help dont understand tryed once got them wrong thank u... 1.Write the formula for mercury(II) chloride 2.Ammonia, NH3, is a typical ingredient in household cleaners. It is produced through a combination reaction involving N2(g) and H2(g). If 24.0 mol of H2(g) react with excess N2(g), how many moles of ammonia are produced? 3.Complete and balance the following equation. Then write it as a net ionic equation. K3PO4(aq) + MgCl2(aq) 4.Convert 4.3 kilograms to centigrams using dimensional analysis. 5.explain how the atoms of one element differ from those of another element. 6.What determines whether one metal will replace another metal from

OpenStudy (anonymous):

Hg2Cl2

OpenStudy (anonymous):

\[3H2+N2\rightarrow2NH3\] so 3:1:2=24:8:16 ans : 16

OpenStudy (anonymous):

can u show me the math caulations on how u got 16

OpenStudy (anonymous):

3:2= (H2:NH3)=24: 16 (the question says you use 24 moles of h2)

OpenStudy (anonymous):

24/3=8 8X2=16

OpenStudy (anonymous):

K3PO4+MgCl2->KCl+Mg3(PO4)2 then K3PO4+3MgCl2->KCl+Mg3(PO4)2 so we got 6cl on left then K3PO4+3MgCl2->6KCl+Mg3(PO4)2 so we got 6kon right then 2K3PO4+3MgCl2->6KCl+Mg3(PO4)2

OpenStudy (anonymous):

@jbarber do you understand those above?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

that's great!

OpenStudy (anonymous):

and sorry I have no confident to give you great response for the left i don't think my response could be professional enough. But I think you can find professional expressions on the Net

OpenStudy (abb0t):

Can you show us your work to see where you mighyt have made a mistake?

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