Question

A group of 3 boys and 2 girls are seated in a row of 5 chairs find the probability that they will be seated alternately..plz help..

Answer 1

You just have to find the number of ways they can sit, then find the number of ways they can sit alternately.

Answer 2

5! = 5 x 4 x 3 x 2 x 1

= 120 ways

Answer 3

And the number of ways in which they can sit alternately is \(3 \times 2 \times 2 \times 1 \times 1\)

Answer 4

3x2x2x1x1

Answer 5

so??what is the answer?

Answer 6

Number of ways they can sit alternately divided by the total number of ways.

Answer 7

@ParthKohli is right. My fault. Looked at the problem a lil bit different. My fault.

Answer 8

thank you..

Answer 9

3!2! divided by 5!??is that correct??

Answer 10

24

Answer 11

yes, that is right.

Answer 12

3C1x2C1x2C1=12...i think its 12...

Answer 13

yes.

Answer 14

12/120 = ...

Answer 15

1/10

Answer 16

Yeah!