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Find the number of ways in which 5 men and 4 women can be seated round a table so that no two women are together.
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If no two women are together, then we have an alternate sitting pattern: a man, then a woman, a man and so on.
so there are (5-1)!*4! right?
We can't have two men together, right? If we do, then there must be a place where two women are together.
I think it is just \(5!4!\)
but it is in a round table.....
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Ah! Yes.
am I right?
Yes
thanks a lot.... :)
No problem!
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You did more of the work. lol
:)
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