Isn't it IODINE ? Which of these elements become cations with positive oxidation states? A.Iodine B.Potassium C.Rubidium D.Selenium
@ParthKohli hey ! do you have a idea of what it is ?
why do you think its iodine?
oxidation numbers are the same thing as valences correct ? @aaronq
valences? you mean valence electrons well sort of, oxidation state refers to the number of electrons the element, typically, likes to gain or lose
so elements initially with 1 or 2 valence electrons will lose to achieve an energetically favoured configuration (an "octet") and those with 6 or 7 will gain e
so am i rifht for thinking iodine is correct ? cause there's several such elements, iron being the most common one. Others include copper, manganese, lead, and cobalt. Nitrogen, chlorine, bromine, iodine, sulfur, and phosphorus also qualify, in their oxyanions.
transition metals such as iron, copper, lead can have several oxidation states, they can be cations but they're a little trickier. You just said it yourself, elements on the right side of the periodic table (halogens , group 6) tend to make anions, (oxyanions are oxygen containing compound that are negatively charged but don't really fall into your category of studying oxidation states), while ones on the left make cations, normally.
all you gotta do, now, is categorize the elements given into their position on the periodic table
@aaronq the oxidation number for potassium is +1. It is that because it wants to lose an electron to have a full octet. If it loses electrons, it becomes a positive number!
yep! thats correct
but so des rubidium lol I'm confused now!
they both do, i guess whoever thought of this question did not take into account the multiple answers that could be right
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