Question

conditions for using the normal approximation for a sampling distribution of means?

Answer 1

@ash2326 @hartnn @ZeHanz @TuringTest @sauravshakya anyone know?

Answer 2

If the no. of means approaches a large number, then the distribution can be approximated as Normal Distribution.

Answer 3

ok thats what i had ! thanks! do u know this one?

Answer 4

Describe the sampling distribution of x-bar for samples of size 20 drawn from a normal population with a mean of 50 and standard deviation of 4.

Answer 5

i dont get it

Answer 6

@ash2326

Answer 7

We need to describe it, maybe we have to find it's probability distribution function pdf

Answer 8

It has to be normal obviously
mean we have 50
and standard deviation 4

Answer 9

ok

Answer 10

what else?

Answer 11

\[\large f(x)=\frac 1 {\sqrt {2 \pi} \sigma}\times e^{\frac{x-\mu}{2\sigma^2} }\]
put
\[\sigma =4\]
\[\mu =50\]

Answer 12

@schmidtdancer I think probably I'm correct. But do get somebody to check it once

Answer 13

So what dhould i put as my answer?

Answer 14

f(x)

Answer 15

for \[-\infty<x<\infty\]

Answer 16

sorry lol, what do i put?

Answer 17

@ash2326

Answer 18

im confused on what to put for my answer

Answer 19

Put the distribution saying the distribution is approximated to normal distribution

Answer 20

all i have is It has to be normal. The mean is 50 and the standard deviation is 4.

Answer 21

yes, put the distribution f(x) what I have posted

Answer 22

Can u repost?

Answer 23

\[\large f(x)=\frac 1 {\sqrt {2 \pi} \sigma}\times e^{\frac{x-\mu}{2\sigma^2} }\]
\[\sigma=4\]
\[\mu=50\]

Answer 24

how do i write that in word form? @ash2326

Answer 25

I got this f(x) = 1 / sqrt(2pi*mean) i cant figure out the rest

Answer 26

* exponential( (x^2-mean)/(2*standard deviation^2))

Answer 27

This ?
f(x) = 1 / sqrt(2pi*mean)* exponential(x^2-mean)/(2*standard deviation^2))

Answer 28

@ash2326 ?

Answer 29

Yes, sorry my net was giving me problems