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If f(x) = x plus 2, all over 2, then what is f^-1(x) ?
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\[y=\frac{x+2}{2}\] The next step is to interchange x and y. Do you want me to take you thru it?
2(x-1)
=2(x-1)
yes, i don't understand this kind of problem
okay let's do it step by step
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When we interchange x and y we get \[x=\frac{y+2}{2}\] Now we need to solve for y by multiplying both sides by 2 giving\[2x=y+2\] Now you can subtract 2 from both sides to find y which is \[f ^{-1}(x)\]
so then, it would be 2x - 2 = y, right?
@DeadShot Good work. Youare correct. You can factorise 2x - 2 = 2(x - 1)
f(x) = (x+2)/2 =>y=(x+2)/2 2y= x+2 x=2y-2 x=2(y-1) find f^-1(x) f^-1(x) = 2(x-1)
Thanks!
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You're welcome :)
you are welcome Deadshot
so is it 2x-2 or 2x-1?
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