Find the equation of the secant line containing (1, f(1)) and (6, (f(6))
f(x)=x^2-2x
Write the coefficients of the equation in the form of a simple fraction

Question

Find the equation of the secant line containing (1, f(1)) and (6, (f(6)) 
f(x)=x^2-2x
Write the coefficients of the equation in the form of a simple fraction

anonymous · Answer

The secant line is the average slope, use the standard equation of a slope. $$\frac{ y1-y0 }{ x1-x0 }$$

You have two points (x=1,y=f(1)) and (x=6,y+f(6))

solve for f(1) and f(6) and use the slope equation.

anonymous · Answer

f(1)=-2 and f(6)=24 right?

anonymous · Answer

$$f(1)=1^{2}-2(1)= -1$$ $$f(6)=6^{2}-2(6)=24$$

anonymous · Answer

where do you plug those values in?

anonymous · Answer

Think of this "f(x)" as a function. You give me an "x" value and I will tell you what "y" is. This is because "y" is DEPENDENT on what the "x" value is. "x" is the INDEPENDENT variable. 

Plug the value given, lets say 6 in the case of "f(6)" into your equation "f(x)" and f(x)=x^(2)-2x

anonymous · Answer

Then take those values as being your two "y" points. Remember which one is y1 nad which is y0 and plug that into the slope equation.

anonymous · Answer

got it! thank youuu

anonymous · Answer

No problemo