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just help me set it up and I'll solve it :) Find the volume of the solid obtained by rotating the region bounded by the given curves about the specified axis. y=x^2, y=0, x=2, about the y-axis
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If you visualize the graph of y (where y=0 and x=2 are boundaries), you will see that its domain is in the first quadrant from y = 0 to 4. We need it in terms of y if we want to use the disc method, so x = sqrt{y}. Therefore integrate \[\pi \int\limits_{0}^{4}(\sqrt{y})dy\]
I got 12pi?
I had 16pi/3
nope thats wrong... mine is too
I forgot to square the radius. Integrate y.
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pi(y^2/2) from 0 to 4
8pi
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