How many dots should be drawn in the Lewis-dot structure for a fluorine atom? Isn't it 7?
wait are you asking for how many dots you should put for fluorine itself alone?
Lewis dot structures show valence electrons which are represented as dots placed around the element symbol. source: textbook, bit of knowledge on the topic, searching :)
Unpaired valence electrons represent electrons available for bonding or for linking with other elements. Elements with the same number of valence electrons have the same Lewis dot structures. source: textbook, bit of knowledge on the topic, school pdf/provided :)
okaii so based on what your question reads, i believe that 7 dots should be drawn in the Lewis-dot structure for a fluorine.
this is because the valence electrons of the element are the number of dots you draw in Lewis-dot structure which goes around the fluorine chemical symbol.
what about this ? I need help!! @some_someone
yes, what do you need help on?
@some_someone
well first, you should try posting this question in the Chem section not Bio, so that i, and other fellow users can help you :)
so you do know that its propane + oxygen -----> Carbon Dioxide + Water right?
To balance an equation, we place numbers in front of the formulas until the number of each kind of atom in the products is the same as that in the starting materials. These numbers are called coeffi cients. So use these steps to balance your equation: 1. Begin with atoms that appear in only one compound on the left and only one compound on the right. In the equation for the reaction of propane and oxygen, begin with either carbon or hydrogen. 2. If an atom occurs as a free element—as, for example O2, in the reaction of propane with oxygen—balance this element last. 3. You can change only coeffi cients in balancing an equation; you cannot change chemical formulas. For example, if you have H2O on the left side of an equation but need two oxygens, you can add the coeffi cient “2” to read 2H2O. You cannot, however, get two oxygens by changing the formula to H2O2. Doing so would change the chemical composition of the expected product from water, H2O, to hydrogen peroxide, H2O2. In the equation for the combustion (burning) of propane with oxygen, we can begin with carbon. Three carbon atoms appear on the left and one on the right. If we put a 3 in front of the CO2 (indicating that three CO2 molecules are formed), three carbons will appear on each side and the carbons will be balanced. Next, we look at the hydrogens. There are eight on the left and two on the right. If we put a 4 in front of the H2O, there will be eight hydrogens on each side and the hydrogens will be balanced. The only atom still unbalanced is oxygen. Notice that we saved this reactant for last (rule 2). There are two oxygen atoms on the left and ten on the right. If we put a 5 in front of the O2 on the left, we both balance the oxygen atoms and arrive at the balanced equation. At this point, the equation ought to be balanced, but we should always check, just to make sure. In a balanced equation, there must be the same number of atoms of each element on both sides. A check of our work shows three C, ten O, and eight H atoms on each side. The equation is indeed balanced. SO AT THE END YOU WILL HAVE SOMETHING LOOKING LIKE THE FOLLOWING: \[C _{3} H _{8}(g) + 5O _{2}(g) \rightarrow 3CO _{2}(g) + 4H _{2} O(g)\]
hope it helps :)
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