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Mathematics 12 Online
OpenStudy (anonymous):

Which equation does not define a function?

OpenStudy (anonymous):

OpenStudy (anonymous):

so do you have any clue or guess of which one it is? give it a try?

OpenStudy (anonymous):

ok well the first one y^2 + x = 6 is a parabola

OpenStudy (anonymous):

no clue i was hoping you would tell me the steps

OpenStudy (anonymous):

so a would be a function right?

OpenStudy (anonymous):

also y - x^2 = 4 is a parabola hence the x or y term is squared.

OpenStudy (anonymous):

so it would be b?

OpenStudy (anonymous):

or am i wrong?

OpenStudy (anonymous):

or a im not sure

OpenStudy (anonymous):

If you graph the first one, it shows a parabola opening to the right. It doesn't pass the vertical line test, so it's not a function.

OpenStudy (anonymous):

is this correct?

OpenStudy (anonymous):

ok you could use the vertical line test. you know how?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

ok does this one pass the vertical line test?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

ok how about this one?

OpenStudy (anonymous):

nope

OpenStudy (anonymous):

x value must have a unique y value right?

OpenStudy (anonymous):

so to pass the vertical line test, the vertical line will NOT cross the graph at more than one point. does this occur in the graph above ?

OpenStudy (anonymous):

how about this other graph? does it pass the vertical line test?

OpenStudy (anonymous):

no it doesn't

OpenStudy (anonymous):

but how would i graph this equation

OpenStudy (anonymous):

also a funtion means that it passes the vertical test?

OpenStudy (anonymous):

btw thanks for helping me study your a big help i was so confused but now i see how easy it is.

OpenStudy (anonymous):

yes, and in other words, a function is defined by the rule: for each value of x there is a single value for y.

OpenStudy (anonymous):

can you just tell me this last thing how do i graph/enter this into a calculator

OpenStudy (anonymous):

and this would be the other graph.

OpenStudy (anonymous):

and no problem :)

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