8z + 3 – 2z < 51
Subtract 3 from both sides.
so subtract 3 from 8 and 51?
Subtract 3 from both sides, add like terms (8z - 2z) and then divide by what's left to get z (6z < 48)
No when you subtract 3 from the left side, it gets eliminated. Never subtract a number with a number and a coeeficient/variable
Why would you subtract 3 from 8? There is no "8". It is "8z". Combine "like" terms only! 3 - 3 leaves zero on the left. 51 - 3 leaves 48 on the right.
tkhunny im pretty sure i am asking for help so i really dont know why i would. ok
\[8z + 3 -2z <51\] Subtract 3 from both sides, eliminating 3 on the left side, and giving you 48 on the right. \[8z -2z < 48\] Add like terms \[6z < 48\] Final answer is z <8
When you're dealing with problems dealing with the "<" and ">" signs, remember that you have to switch the sign around when you divide by a negative number. in this case, you didn't have to
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Thank you i have been out of school far to long and math was never my strong subject. appreciate the patience.
ur welcome :)
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