Question

Factor the following:
1. 25a2 + 40x + 16
2. 6y2 + 5y + 1
3. 20z2 + 22z - 12
4. a2 + 3ab - 4b2

PLEASE HELP & EXPLAIN HOW TO DO THEM

Answer 1

fo number two i would us "AC Method"

Answer 2

okay, explain what that is

Answer 3

so here it goes:
to use this method, the expression has to be in AX^2 + Bx + C form okaii.

Answer 4

get it until now?

Answer 5

i dont want to loose you early?

Answer 6

yess!! that makes complete since, the a,b and c will be filled in with the number in the question. lol: a is 6, b is 5,c is 1, okay go(:

Answer 7

ok good :)

Answer 8

Steps:
1.) multiply AC
2.) Find 2 integers such that the product equals AC and the sum equals B
3.) Rewrite the Original problem by using A,C, and the 2 new integers.
4.) Factor by using Grouping.

Answer 9

r u still good until now?

Answer 10

1.) would that just stay 6 cuz 6*1=6 or would it be 12 because u do 6^2*1

Answer 11

or i mean 6^2*1=36 lol

Answer 12

no, ur right :0 it would be 6

Answer 13

okayy! then i get confused on 2.)

Answer 14

keep going :)

Answer 15

the 5y+1= 6. is that what u mean?

Answer 16

get it:)

Answer 17

so for step 2, you got the 3 because 3 goes into 6 twice? right? then step 3 u just rewrote the problem with the new equation and step 4 u grouped everything. yes?

Answer 18

haha im alittle confused on the last problem u drew

Answer 19

for step 2 i used those numbers (3 and 2) because when multiplied it equals 6, right?
but when you add 3 + 2 = 5
hence the A = 6 AND B = 5

Answer 20

okay, i get it(: just couldnt explain what i was thinking

Answer 21

i think the GCF of all the things in #1 is one so im guessing it can only be factored to 1(25a2+40x+10) That doesnt really go down that much so i may be wrong

Answer 22

@JaneDoe100 ur correct that is what i told her earlier but i deleted my post, to not get her confused. i would say that it is prime, dont you think?

Answer 23

so it would be a=4,3 because 4*-1=-4 but 4+-1=3?

Answer 24

a=-4,3*

Answer 25

OHHHHH, yesssss i seee, i see.

Answer 26

ok lets start over on # 4, cause i read it wrong on ur question lol sorry :(

Answer 27

a^(2)+3ab-4b^(2)

In this problem 4*-1=-4 and 4-1=3, so insert 4 as the right hand term of one factor and -1 as the right-hand term of the other factor.
(a+4b)(a-b)