Ask your own question, for FREE!
Geometry 19 Online
OpenStudy (anonymous):

I need help! please help anyone?! What are the values of a and b?

OpenStudy (anonymous):

OpenStudy (anonymous):

a. a=9/2, b=15/2 b. a=15/2, b=9/2 c. a=16/3, b=15/2 d. a=9/2, b=13/2

OpenStudy (anonymous):

from big triangle, b^2+10^2=(a+8)^2 from small triangle, a^2+6^2=b^2 so comparing value of b^2 we get, a^2+6^2+10^2=a^2+16a+64 =>136-64=16a =>72/16=a =>a=9/2 so, b=sqrt(a^2+6^2)=sqrt(81/4+36)=sqrt(225/4)=15/2 now you find your answer

Directrix (directrix):

Theorem: If the altitude is drawn to the hypotenuse of a right triangle, the length of the altitude is the geometric mean between the lengths of the segments of the hypotenuse. So, 8 is to 6 as 6 is to a. 8/6 = 6/a 8a = 36 a = 4.5 -->

Directrix (directrix):

Theorem: If an altitude is drawn to the hypotenuse of a right triangle, either leg of the triangle is the geometric mean between the length of the hypotenuse and the segment of the hypotenuse adjacent to that leg. The hypotenuse is (4.5 + 8) = 12.5 The segment adjacent to the leg with length b = 4.5. 4.5 is to b as b is to 12.5 4.5/b = b/12.5 b^2 = (4.5)*(12.5) Solve for the positive square root of b. @dragontales

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!