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Find the value of the 90th percentile of the following set of data 18,9,7,5,11,7,20,19,2,17,12,5,1,13,12,11,15,16,20
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n = 19 scores mean = 11.58 pop standard deviation = 5.81 The z-score for the 90th percentile is approximately 1.28. 1.28 = (x - 11.58)/5.81 x = 19.02 --> The score of 19 is at the 90th percentile.
Please check the work above. Tools: Online standard dev and mean calculator http://easycalculation.com/statistics/standard-deviation.php Tutorial on Standard Normal Curve and 90 th Percentile http://tinyurl.com/ahxzwwe Public Domain Tables of Normal Distribution http://www.math.unb.ca/~knight/utility/NormTble.htm
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