Question

Show that square root of i= 1+i/square root of 2.
Plz Help me as fast as u can!

Answer 1

try to find what \[(\frac{1+ i }{ \sqrt{2} })^{2}\]
is

Answer 2

um go to math .com

Answer 3

Do you know what i stands for?

Answer 4

i = square root of -1

Answer 5

Plz can you solve for me?
I am in an urgent condition.

Answer 6

Im having a hard time solving, I will send someone to help.

Answer 7

@phi maybe able to help.

Answer 8

Show that square root of i= 1+i/square root of 2.
\[ \sqrt{i} = \frac{1+i}{\sqrt{2}} \]

square both sides
\[ i = \left(\frac{1+i}{\sqrt{2}} \right)^2 \]

square the right-hand side. Treat i as an ordinary variable and this is just like the multiplication of the binomial (1+x)*(1+x). After doing the multiplication, replace any i^2 term with -1 and simplify