is (-4,7) the intersect of both lines when solving for x + 2y = 10, and 3x + 4y = 8?
This is solving systems of linear equations. x + 2y = 10 3x + 4y = 8 Any idea how to go about this?
Yeah x + 2y = 10 the answer is y = 5 (0,5) and x = 10 (10,0) for 3x + 4y = 8 the answer is (0,2) for y and the slope is -3/4. I'm just wondering if (-4, 7) is the correct intersect on both lines
Oh... Graphing is a terrible way to solve systems, it's too... prone to human error. Here's an easier way :) Substitute -4 for x, and 7 for y. In the first equation x + 2y = 10 substituting -4 + 2(7) = 10 Is it valid?
-4 + 2 * 7 = 10 yes its true
Okay, so what does that tell you? It tells you that the point (-4 , 7) is on the line x + 2y = 10 But is it also on the line 3x + 4y = 8 ? Substitute and see.
3 * -4 + 4 * 7 = 8 false, the answer is 16
Then that can only mean that the point (-4, 7) is not on the line 3x + 4y = 8 What can you conclude now?
(-4,7) isn't going the intersect of both equations
Precisely :)
How do I find the intersect of both equations then?
Oh, well, let's go back to basics :D Remember your properties of equality?
nope
Okay, let a, b, c, d be real numbers If a = b then ca = cb correct?
yes
also, if a = b and c = d Then a + c = b + d Right? We just added the left sides and the right sides of the equations
yes
have you done metrics for 2x2 system it is a simple as solving by substitution
as simple as*
x + 2y = 10 3x + 4y = 8 We can add the left sides and the right sides, and it gives us x + 3x + 2y + 4y = 18 4x + 6y = 18 But that's not really that helpful, is it? :P
have you learn substitution or elimination method?
This is the elimination method, by the way.
What do we do after we add both sides?
We don't. I'm just demonstrating adding both sides right away, and how useless it is :) Now remember, that first property I showed you, where we multiply the same number on both sides of the equation?
Do you know what the problem I'm doing is called so I can find a video on www.khanacademy.org and see live examples?
Systems of Linear Equations.
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