find the linear approximation of the funtion f(x,y )= sqrt 20-x^2-7y^2 at (2,1). use your answer to aproximate f(1.95, 1.08)
http://en.wikipedia.org/wiki/Linear_approximation a=2 b=1 then find partial derivatives wrt x and wrt y sub everything into formula
f (2,1)+ sqrt 2x (x+2) + sqrt 14y ( y-1)
why is it sqrt(2x) ? is everything inside radical?
yes
i think is 1/2 ( 2x) ^-1/2
1/ sqrt 2x
hmm \[d/dx \sqrt{20-x^{2}-7y^{2}} = \frac{-2x}{2\sqrt{20-x^{2}-7y^{2}}} = \frac{-x}{\sqrt{20-x^{2}-7y^{2}}}\]
ok forget about that
\[d/dy = -7y/\sqrt{20-x^2-14y^2}\]
right
oh should still be 7y^2 in radical
after plugging in (2,1) i get \[f(x,y) \approx 3-\frac{4}{3}(x-2)-\frac{7}{3}(y-1)\]
@dumbcow after that i need to aproximate f(1.95, 1.08) doing the same thing that we did with (2,1)
no we already have the linear approximation plug in (1.95,1.08) for (x,y)
@dumbcow ok
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