Question

Hey, I had a question about an answer on a question... please look at http://openstudy.com/study#/updates/5054c511e4b0a91cdf44666c and answer my question

Answer 1

Why does it not times the 2 (the radicand) as well?

Answer 2

Since it was in the parenthesis shouldn't it be multiplied too?

Answer 3

or do you not times the radicand when finding the perimeter of a rectangle?

Answer 4

Where do you have doubt in this?
\[2(\sqrt{128}+\sqrt{200})= 2(8 \sqrt 2+ 10 \sqrt 2)= 2(18 \sqrt 2)=36 \sqrt 2\]

Answer 5

@that1chick

Answer 6

2(√128+√200)=2(8√2+10√2)=2(18√2)=36√2
or 36√4?

Answer 7

sorry my computer is being slow

Answer 8

I just need to know if you times the radicand?

Answer 9

Well, wouldn't you ask that in the other question ask the person who posted it?

Answer 10

you have
\[2\times18 \sqrt {2}\]
you'll just multiply it by 18
\[36\sqrt 2\]

Answer 11

It was posted a while ago... and I did

Answer 12

@EvonHowell it's ok to ask as a new post. It's related to maths

Answer 13

so in 2(18√2) you would only times the 18 by 2?

Answer 14

@that1chick If you have
\[2\sqrt 2\]
then it's two times the radicand

Answer 15

yes, if you have
\[2\times (4\times 6)\]
Would you multiply it to both 4 and 6?

Answer 16

Yes, I know it is I was just saying.. LOL but that question was asked 5 Months ago so I understand now :)

Answer 17

Cool :)

Answer 18

@that1chick do you get my point?

Answer 19

Ok I get it... they shouldnt have put it in parenthesis. Thank you

Answer 20

Nope, they can put in parenthesis.
If you have
\[a(b+c)=a\times b+a\times c\]
\[a(b\times c)=(a\times b)c=a\times b\times c\]

Answer 21

are you saying that it didnt change the radicand because it was applied to the value being times by the radical and therefor would be applied that way

Answer 22

It's applied to the whole term
if you have 2 *(4*6)
you apply 2 to either 4 or 6 not both.
In our case we have a radical
so it's applied to 18, it can be applied to radical also
\[2\times (18\sqrt {2})=18\times 2\sqrt 2\]
Take the 2 inside
\[18\times \sqrt{4\times 2}=18\sqrt 8\]
radical is just a no.

Answer 23

Oh okay... x the other value makes it towhere you dont have to simplify again... I get it now, thank you

Answer 24

Good :) welcome