Question

If f(x) = x^2-sqrt(x)+6, find f'x.

Answer 1

\[f(x)=x ^{2} -\sqrt{x}+7\]

Answer 2

have u tried it yet?

Answer 3

I did this:
\[f'(x) \lim_{h \rightarrow 0} \frac{ (a+h)^{2}-\sqrt{a+h}+7-a ^{2} +\sqrt{a} -7}{ h }\]

Answer 4

thats right

Answer 5

\[\frac{2ah+h ^{2} -\sqrt{a+h} +a}{ h }\]
then, the professor told me to solve them separately. so I get:

Answer 6

hey its:
2x -1/2 x ^-1/2
:)

Answer 7

\[\frac{ 2a+h+h ^{2} }{ h } =2+h\]

Answer 8

right! I just automatically write a's because thats the formula. ;)

Answer 9

and for the other one is when I get a little bit confused. I just multiply by the conjugate. and get \[\frac{ 1}{ \sqrt{a+h} +\sqrt{a}}\]
so if I combine them I get:
\[2+h -\frac{ 1 }{\sqrt{a+h} +\sqrt{a} }\]

Answer 10

is this correct??