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Algebra 8 Online
OpenStudy (anonymous):

Help!

OpenStudy (zehanz):

I think it is \[y=\frac{ 3 }{ 4x-12 }\]

OpenStudy (zehanz):

We can rewrite this one as:\[y=3 \cdot \frac{ 1 }{ 4(x-3) }=\frac{ 3 }{ 4 }\cdot \frac{1}{x-3}\]Do you know what the factor 3/4 does with a graph?

OpenStudy (zehanz):

It shrinks with respect to the x-axis. This means, if your original graph went through, say, (2, 10), the new grapg goes to (2, 7.5). Every point gets closer to the x-axis, the distance to it only 3/4 of what it was. Hope you understand :)

OpenStudy (zehanz):

So you also understand that the graph has moved 3 units to the right! To be honest, I do not understand the second part of the question either :(

OpenStudy (zehanz):

Hold on, lemme think about it...

OpenStudy (zehanz):

What about f(x)=1/(x²+1) ? It is a rational expression, and x²+1 is always positive, so there is no chance of division by zero, so no vertical asymptote!

OpenStudy (anonymous):

what about no hole

OpenStudy (zehanz):

@lala2: you're not the patient type, are you ;)

OpenStudy (anonymous):

sorry!just eager to understand

OpenStudy (zehanz):

No problem! THere is no hole, because the domain is all real numbers.

OpenStudy (anonymous):

oh ok.. that makes sense! thanks for all of your help!

OpenStudy (zehanz):

YW!

OpenStudy (anonymous):

3 medals? Nice...

OpenStudy (zehanz):

@Dthnider: That's what I thought!

OpenStudy (anonymous):

:O I know right @ZeHanz

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