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Limestone is a binary mixture of calcium and magnesium carbonates, CaCO3 and MgCO3. At 500 C, MgCO3 thermally decomposes according to the reaction shown, while CaCO3 remains unchanged. MgCO3(s)=MgO(s)+CO2(g) When heated at 500C, a 2.000g sample of limestone from a local quarry loses 0.273g. Calculate mass percent of MgCO3 present in the limestone. I worked it out using both algebraic and theoretical yield methods, and got different answers. Help please!
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show your work, ill tell you where you went wrong
I think I may have corrected it, would this be right? .273g CO2->mols CO2->molsMgCO3->.523gMgCO3 (.523gMgCO3/2.00g mixture)(100%)=26.18% MgCO3
yeah that looks correct
Looks good to me too!
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