Question

urn contains 4 white and 6 red rolls. Four balls are drawn at random (without replacement) from the urn. Find the probability distribution of number of white balls?

Answer 1

Probability distribution
W 0 1 2 3 4
P(W)
We need to find the probability for each of the case, then we need to fill the table.
Do you get this @msingh

Answer 2

yup

Answer 3

First case 0, white, It;s easy
Can you find the probability of getting all 6

Answer 4

red

Answer 5

hmmm.
no

Answer 6

Choosing 4 out of 6 red= 6C4
Choosing 4 out of 10=10C4
\[P(W=0)=\frac{^6C_4}{^{10}C_4}\]
Do you get this?

Answer 7

yes

Answer 8

okay when
no white balls --- (3/5)^4 = 81/625
one white ball -- C(4,1) (2/5) (3/5)^3 = 216/625
two white balls -- C(4,2) (2/5)^2 (3/5)^2 = 216/625
three white balls -- C(4,3) (2/5)^3 (3/5) = 96/625
four white balls -- (2/5)^4 = 16/625

Answer 9

is it right

Answer 10

How did you find 1 white?

Answer 11

i copy from somewhere

Answer 12

I think you have replaced them back. Yes copying never helps

Answer 13

k

Answer 14

Did you understand how I found probability for first case W=0?

Answer 15

yes

Answer 16

For second case W=1 R=3
\[P(W=1)=\frac{^4C_1\times^6C_3}{^{10}C_4}\]
1 blue out of 4, 3 red out of 6
4 out of 10

Answer 17

k

Answer 18

@msingh are you getting this?

Answer 19

yes

Answer 20

@ash2326
where r u