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Mathematics 15 Online
OpenStudy (anonymous):

The weights of packages of crackers follow a normal distribution with a mean of 15.2 oz. and a standard deviation of .5 oz. If x-bar is the mean weight of a SRS of 7 packages of crackers, then x-bar has an _______

OpenStudy (anonymous):

@jim_thompson5910

OpenStudy (anonymous):

OPTIONS: (a) approx distrib with mean=15.2 and SD= .2 (b) exact normal distrib with mean=15.2 and SD=.4 (c)approx distrib with mean=15.5 and SD= .2 (d) approx distrib with mean= 15.5 and SD= .4 (e) exact distrib with mean=14.6 and SD= 1

jimthompson5910 (jim_thompson5910):

well if X is normally distributed then Xbar is normally distributed

OpenStudy (anonymous):

Ok

jimthompson5910 (jim_thompson5910):

oh sry i should add: Xbar is normally distributed for large values of n Xbar is approximately normally distributed if X is normally distributed and n is a small number

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

which option would that be?

OpenStudy (anonymous):

?

jimthompson5910 (jim_thompson5910):

what do you think?

OpenStudy (anonymous):

uh

jimthompson5910 (jim_thompson5910):

keep in mind that if X is normally distributed with mean mu and standard deviation sigma, then Xbar is approximately normally distributed (for n < 30) with mean = mu standard deviation = sigma/sqrt(n)

OpenStudy (anonymous):

so is it either a or d?

jimthompson5910 (jim_thompson5910):

why d?

OpenStudy (anonymous):

I mean, i think its a but im not sure

jimthompson5910 (jim_thompson5910):

mean = 15.2 so it's either A or B

jimthompson5910 (jim_thompson5910):

is it exactly normally distributed? or approximately normally distributed?

OpenStudy (anonymous):

Umm norma?

OpenStudy (anonymous):

approx

jimthompson5910 (jim_thompson5910):

good

jimthompson5910 (jim_thompson5910):

so it can't be B because that's exact

jimthompson5910 (jim_thompson5910):

it's approx since n = 7 is definitely less than n = 30

OpenStudy (anonymous):

So A then

jimthompson5910 (jim_thompson5910):

yes

OpenStudy (anonymous):

yay! ok like one more ill post now thanks so much

jimthompson5910 (jim_thompson5910):

alright

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