The weights of packages of crackers follow a normal distribution with a mean of 15.2 oz. and a standard deviation of .5 oz. If x-bar is the mean weight of a SRS of 7 packages of crackers, then x-bar has an _______
@jim_thompson5910
OPTIONS: (a) approx distrib with mean=15.2 and SD= .2 (b) exact normal distrib with mean=15.2 and SD=.4 (c)approx distrib with mean=15.5 and SD= .2 (d) approx distrib with mean= 15.5 and SD= .4 (e) exact distrib with mean=14.6 and SD= 1
well if X is normally distributed then Xbar is normally distributed
Ok
oh sry i should add: Xbar is normally distributed for large values of n Xbar is approximately normally distributed if X is normally distributed and n is a small number
ok
which option would that be?
?
what do you think?
uh
keep in mind that if X is normally distributed with mean mu and standard deviation sigma, then Xbar is approximately normally distributed (for n < 30) with mean = mu standard deviation = sigma/sqrt(n)
so is it either a or d?
why d?
I mean, i think its a but im not sure
mean = 15.2 so it's either A or B
is it exactly normally distributed? or approximately normally distributed?
Umm norma?
approx
good
so it can't be B because that's exact
it's approx since n = 7 is definitely less than n = 30
So A then
yes
yay! ok like one more ill post now thanks so much
alright
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