Question

Using the normal distribution to approximate a sampling distribution of proportions is acceptable provided that:

Answer 1

(a) np</=10 and n(1-p) </= 10
(b) np>/=10 and n(1-p) >/= 10
(c) np=10 and p(n-1)> 10
(d) np<10 and n(1-p)<10
(e) np </= 10 and n(1-p) >/= 10

Answer 2

@jim_thompson5910

Answer 3

which one do you think it is

Answer 4

b

Answer 5

but im not really sure

Answer 6

you are 100% correct

Answer 7

I used 5 in my last requirement, but they want it to be more accurate and are going for 10

Answer 8

Yay!

Answer 9

wait what? its b right

Answer 10

basically, you want both np and n(1-p) to be large enough (in this case, both need to be at least 10)

Answer 11

so what was the answer to the last one?

Answer 12

the other choices have < signs which don't make any sense

Answer 13

yeah it's B, you got it right

Answer 14

Ok! and last one: In a large population, 46% of the households own VCR's. A simple random sample of 250 households are contacted and asked if they own a VCR and the proportion is computed. What is the mean of the sampling distribution of the sample proportion?

0.0023

0.046

0.46

0.54

4.6

I GOT C, can u just check

Answer 15

@jim_thompson5910

Answer 16

NEVER MIND! i got it. thanks for all ur help

Answer 17

you are correct, nice work

Answer 18

sry OS is glitching on me, but I'm glad you figured it out