Question

Suppose u(t)=w(t^2+1) and w′(2)=11 . Find u′(1) .

Answer 1

Its a composite function... Simply Diffrentiare it...

Answer 2

2t

Answer 3

lets try this
\[u(t)=w(t^2+1)\]
\[u'(t)=w'(t^2+1)\times 2t\] by the chain rule
so
\[u'(1)=w'(1^2+1)\times 2\times 1=w'(2)\times 2=11\times 2=22\]

Answer 4

thank you!