Hey I was wondering if someone could explain this for me: If the ball makes two complete revolutions per second, then the ball travels in a complete circle in a time interval equal to 0.500 s...
I like to know how you go about solving this. where does the .500s come from?

Question

Hey I was wondering if someone could explain this for me: If the ball makes two complete revolutions per second, then the ball travels in a complete circle in a time interval equal to 0.500 s...
I like to know how you go about solving this. where does the .500s come from?

anonymous · Answer

So basically whats happening is that the ball is completing 2 revolutions or full circles in one second. So, in a real life situation it could be a fan blade turns a full 360 degrees twice in one second. The .500 s comes from when you want to know how long it takes for it to complete one revolution (or full circle). So if it can go around twice in a second, divide the time by two to find out the time it takes to go around once : .500s.
I hope this makes sense.

anonymous · Answer

yes  but im still a bit confuse bout calcuations..

anonymous · Answer

The problem stated: the ball make 2.00 rev/s how would you go about doing this?

anonymous · Answer

I will check back but ill give you best response medal

vincent-lyon.fr · Answer

Your problem states the frequency of the motion, and you are asked the period.

What is the relationship between period and frequency?

anonymous · Answer

The relationship between period and frequency is that period is and object revolving in a CiRC|e is the time required for one complete Rev. frequency is # of rev per second

vincent-lyon.fr · Answer

What you have written are definitions of period on one hand and frequency on the other.

It is not a relationship between them.

anonymous · Answer

oh so can you explain to me please

vincent-lyon.fr · Answer

If you make 10 revs in one second, how long does it take for 1 rev?

anonymous · Answer

im not sure that's what im trying to understand

vincent-lyon.fr · Answer

Will it take more time, or less time?

anonymous · Answer

less I believe

vincent-lyon.fr · Answer

By how many times?

anonymous · Answer

1/10?

anonymous · Answer

I'm going to refer back to the original problem ok? 
For the actual calculations you can make a ratio and then cross multiply.|dw:1361404827509:dw| 
Now cross multiply this so solve for the question mark.
You should get .500 sec.

anonymous · Answer

Oh I see thanks again

anonymous · Answer

It's beautifully simple. The number of revolutions/cycles per second is defined by a hert, which is the unit of frequency, hertz (Hz)

So for this case, two revolutions per second is 2Hz.

The relationship between the time period and frequency is:

1/f = T       or       1/T = f

basically they're the inverse of each other.

2 revolutions per second, so the time it will take for one revolution would be the 1 second divided by the number of revolutions, i.e 1/2 which is 0.5.