Solve for x (2/5) + (3/5x) = (x+5)/10 I keep getting stuck at 6 = x^2 -x
its quadratic solve it by dharacharyas formula
ans is 13 0r 12
Well, that isn't any of the answers given. We are supposed to be using something similar to how we were simplifying rational expressions. When i follow those steps I find the common denominator, and the corresponding numerators to get: (4x/10x) + (6/10x) = ((x^2 + 5x)/10x) [I distributed the x from x(x+5) that i got from the numerator after finding the corresponding values with the denominator] At this point, my lesson said I should be able to just remove the common denominators and solve for x like normal, but it just isn't working.
4x + 6 = x^2 +5x x^2 + x - 6 = 0 X^2 + 3x -2x +6= 0 x ( x+3) -2 ( x+3) = 0 (x-2) (x+3) =0 x =2 or -3
Oh! That makes perfect sense, and is an answer choice! I see what I did wrong now, I forgot that I was putting the equation equal to 0 Then it was just a matter of factoring! Thank you for the help Meinme :)
mention not....
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