0.491 g of an acid is in a beaker. a buret containing .260 M NaOH is added to the acid. It took 21.0mL to reach end point titration. What is the molar mass of the acid?

Question

preetha · Answer

Write the equation.
moles of acid = molarity of NaOH x volume of NaOH(L)
moles of acid = g/molar mass

anonymous · Answer

ok so i am getting .260(21.0)=5.46moles of acid.
Then .491g/5.46moles=.0899 or 9.00x10^-2 g/mol

anonymous · Answer

But that is wrong

anonymous · Answer

ok I got it. You have to convert the 21.0mL to L to be the same as the M. thank you for your help. I finally got the right answer.