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Chemistry 8 Online
OpenStudy (anonymous):

0.491 g of an acid is in a beaker. a buret containing .260 M NaOH is added to the acid. It took 21.0mL to reach end point titration. What is the molar mass of the acid?

OpenStudy (preetha):

Write the equation. moles of acid = molarity of NaOH x volume of NaOH(L) moles of acid = g/molar mass

OpenStudy (anonymous):

ok so i am getting .260(21.0)=5.46moles of acid. Then .491g/5.46moles=.0899 or 9.00x10^-2 g/mol

OpenStudy (anonymous):

But that is wrong

OpenStudy (anonymous):

ok I got it. You have to convert the 21.0mL to L to be the same as the M. thank you for your help. I finally got the right answer.

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