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OpenStudy (anonymous):
0.491 g of an acid is in a beaker. a buret containing .260 M NaOH is added to the acid. It took 21.0mL to reach end point titration. What is the molar mass of the acid?
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OpenStudy (preetha):
Write the equation. moles of acid = molarity of NaOH x volume of NaOH(L) moles of acid = g/molar mass
OpenStudy (anonymous):
ok so i am getting .260(21.0)=5.46moles of acid. Then .491g/5.46moles=.0899 or 9.00x10^-2 g/mol
OpenStudy (anonymous):
But that is wrong
OpenStudy (anonymous):
ok I got it. You have to convert the 21.0mL to L to be the same as the M. thank you for your help. I finally got the right answer.
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