Question

tan fraction question. I will put the problem below to look pretty

Answer 1

\[\frac{ \tan^{2} x -1 }{ 1+\tan^{2} }\]
I get that \[\tan^2 x +1= \sec^2 x\] but I don't know how to solve for the \[\tan^2x-1\]

Answer 2

so, just change the denominator be sec^2 x, right ?

Answer 3

it can be :