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Mathematics 15 Online
OpenStudy (anonymous):

PLease help!!!!! Find a value for k in the function below so that the function is continuous at all points. f(x)={((x^5-32)/(x-2)) , x≠2, k, x=2 k=

OpenStudy (anonymous):

find the limit at \(x=2\) and replace \(k\) by that number

OpenStudy (anonymous):

it might help to know that \[x^5-32=(x-2) (x^4+2 x^3+4 x^2+8 x+16)\] so you can cancel the factor of \(x-2\) top and bottom and replace \(x\) by \(2\) in \(x^4+2 x^3+4 x^2+8 x+16\) that will be your \(k\)

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