A friend tosses a baseball out of his second floor window with initial velocity of 4.3m/s(42degrees below the horizontal). The ball starts from a height of 3.9m and you catch the ball 1.4m above the ground.
a) Calc the time the ball is in the air (ans. 0.48s)
b)Determine your horisontal distance from window (ans. 1.5 m)
c)Calc the speed of ball as you catch it (ans: 8.2m/s)

I dont get what 42 m below the horizontal is, can someone give me direction on how to do this?

Question

A friend tosses a baseball out of his second floor  window with initial velocity of 4.3m/s(42degrees below the horizontal). The ball starts from a height of 3.9m and you catch the ball 1.4m above the ground.
a) Calc the time the ball is in the air (ans. 0.48s)
b)Determine your horisontal distance from window (ans. 1.5 m)
c)Calc the speed of ball as you catch it (ans: 8.2m/s)

I dont get what 42 m below the horizontal is, can someone give me direction on how to do this?

anonymous · Answer

I believe that the 42 degrees below the horizontal is 42 degrees below 0 / 360 degrees minus 42. I'm not ABSOLUTELY sure, but at least pretty darn sure, because horizontal is the left-right axis, and by average, 0 is perfectly horizontal.

stamp · Answer

@buggiethebug It is not 42 m below the horizontal, it is 42° below the horizontal. m is a  distance, ° is a direction. Hopefully that clears up your comprehension of the problem.

stamp · Answer

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