Question

a/a-8 + a/8-a

Answer 1

i got a/-(a-8)^2

Answer 2

so you are adding 2 fractions

for the 2nd fraction take -1 out as a factor in the denominator. This will then allow you to add or subtract the fractions.


\[\frac{a}{a - 8} + \frac{a}{8 - a} = \frac{ a}{a - 8} - \frac{a}{a - 8} = \frac{a - a}{a - 8}\]

I hope this makes it easy to simplify... just add the like terms in the numerator

Answer 3

so my answer not right....

Answer 4

I'd say so...

once you have the same denominator for both fractions just add or subtract the numerators

Answer 5

yep i did and that's the answer i got...

Answer 6

my final answer

Answer 7

the fraction

\[\frac{a}{8 - a} = \frac{a}{-1(a - 8)} = \frac{-a}{a - 8)}\]

Answer 8

its the same rule as adding fractions if the denominators are the same

\[\frac{2}{7} + \frac{3}{7} = \frac{2 + 3}{7}\]

Answer 9

I'd say you final answer is zero... since

\[\frac{a -a}{a - 8}= \frac{ 0}{a - 8} = 0\]