Differentiate with respect to x: e^(3lnx)
Chain rule.. you know it? :)
yes, but how??
my question was, does e^ln cancel out here?
:Whoops I am shamed for not noticing that :D sorry, do the cancellation first
so what does that become, 3x??
No... remember the properties of logarithms :) \[\huge p \ln x = \ln x^p\]
or should i do the whole f'(x)e^f(x) thing??
That was what I thought, until you reminded me that e^x and ln x cancel out :) See that exponent \[\huge 3 \ln x\] How can you use that property that I showed you?
OMG
Stuck? Something wrong?
I'M AN IDIOT THANK YOU FOR POINTING OUT MY IDIOCY OMG :P
SO SIMPLE
YOU pointed out my idiocy XD
So what's your answer? :D
yuck. we suck :P
3x^2 :D
LOL yeah. Now, for entertainment purposes, let's see what happens if we apply the chain rule... \[\huge \frac{d}{dx}e^{3\ln x}=e^{3lnx}\frac{d}{dx}3\ln x=\frac{3e^{3\ln x}}{x}\] You'd have to simplify the exponential anyway. ANYWAY Great job :)
omg thats scary looking. Well, it's easier than implicit. Actually, implicit's pretty easy :P
and omg thank you SO much. stick around, there are some more questions coming up :)
Sure :)
ok. y = \[x^2\ln (1/x)\]
where x is the ratio of the inner radius to outer radius. the inner radius is 1/2. for max speed, what should be the outer radius?
I've got the answer, i just wanna double check. i have \[\sqrt{e}/2\]
I honestly don't know what these mean :) What's an inner radius?
arrey, imagine a sphere. or say, the earth. so the radius of the core, and the radius of the mantle so to speak.
Okay...
Join our real-time social learning platform and learn together with your friends!