if the radii of the circular ends of a conical bucket in the shape of frustum of a cone which is 45cm high are 28cm and 7cm.find the capacity of the bucket in litres

Question

anonymous · Answer

@terenzreignz

terenzreignz · Answer

Okay... the volume of a frustum, you know the formula? :)

anonymous · Answer

yes

terenzreignz · Answer

What is the formula, then?

anonymous · Answer

v = pi/3 (r^2+R^2+rR)h

terenzreignz · Answer

Yep.  So what's the volume, then? 
By the way, volume = capacity...

anonymous · Answer

= pi/3 (28^2+7^2+28*7)*45 
= 15435 pi 
=15435(22/7)
=48510cm^3

terenzreignz · Answer

Are you sure you want to use 22/7 as pi?
Maybe you could use
$$\large \pi = 3.141592654$$$$\huge \pi=3.1416$$
Although if 22/7 is allowed, I won't contest it.

anonymous · Answer

because it is not given in question that u must use pi as 22/7 or 3.14

terenzreignz · Answer

Well, I don't want to assume.  I'll just leave a factor of pi, and leave the deciding which value for pi you want to use, ok? :)
So...
$$\huge V=\frac{h\pi}{3}\left(R^2 + Rr + r^2\right)$$

anonymous · Answer

thank u so much @terenzreignz

terenzreignz · Answer

Not yet done!
So your volume is 
$$\huge V=15435\pi$$
But this is in cubic centimetres.  You need the volume in litres...

anonymous · Answer

i have to divide it by 1000

terenzreignz · Answer

Okay, good :)
It seems you already knew how to do it, why did you tag me? LOL
Good job, by the way, but I'd suggest you use 3.1416 instead of 22/7
But anyway... nicely done

anonymous · Answer

thank u once again