Question

If I want to change y''+y'+y=x(t)+x'(t) into frequency domain, I know that y''=(jw)^2 and x(t) is just 1 but what about x'(t)? Is it 0?

Answer 1

Actually, I y"(t) in the frequency domain would be \[(j\omega)^2Y(j\omega)\]In the same way, x'(t) would be \[j\omega X(j\omega)\]

Answer 2

Oh I meant the frequency response

Answer 3

So does it just become \[H(jw) = \frac{ 1+jw }{ (jw)^2+jw+1 }\]

Answer 4

That looks about right.

Answer 5

Thanks a lot for your help!! Much appreciate it