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Chemistry 15 Online
OpenStudy (anonymous):

Can someone please help me solve this? The Lyman series in the hydrogen atom consists of transitions to the n=1 level that take place in the ultraviolet part of the spectrum. Calculate the wavelength of the light emitted due to the lowest energy transition of this series between n=2 and n=1levels. I know this is set up so that you have 1/wavelength=1.097x10^-2m^-1[(1/n1^2)-(1/n2^2)], but I'm not sure how to plug in the numbers. Help!

OpenStudy (jfraser):

plug in n=1 for n1 and n=2 for n2 and solve for 1/wavelength, then invert it

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