Question

need help with a log problem. equation will be below

Answer 1

\[\log _{3}1\div \sqrt{3}\]

Answer 2

\[\log_3(\frac{1}{\sqrt{3}})=\log_3(3^{-\frac{1}{2}})\] should help

Answer 3

why -1/2 ? I thought it would be (-1/3)

Answer 4

OMG! Typed it for nothing, I understood your problem wrongly:/ Ah

Answer 5

i am so confused

Answer 6

well, if there are
\[\sqrt{a}\]
it can be written as
\[\sqrt{a}=a^{\frac{ 1 }{ 2 }}\]

Answer 7

do you know this rule?

Answer 8

the inverse right?

Answer 9

i'm not sure what to do with it

Answer 10

You have \[\log _{3}\frac{ 1 }{ \sqrt{3} }\] right?

Answer 11

yes

Answer 12

So,now forget that \[\log _{3}\] thingy for a minute, okay?

Answer 13

okay

Answer 14

\[\frac{ 1 }{ a }=a ^{-1}\] do you agree with it?

Answer 15

yes.

Answer 16

You have
\[\frac{ 1 }{ \sqrt{3} }\]
so do you agree it can be written as:
\[\frac{ 1 }{ \sqrt{3} }=(\sqrt{3})^{-1}\]

Answer 17

yes that makes sense

Answer 18

What do you think about it? It is true? Or not?
\[\sqrt[n]{a ^{m}}=a ^{\frac{ m }{n}}\]

Answer 19

yes it is true

Answer 20

So, you have \[(\sqrt{3})^{-1}\] can you change it as showed above?

Answer 21

do i just assume the n and m are 1 since there isn't an actual number for them?

Answer 22

yes, m=1, but is n=1?

Answer 23

\[3^{\frac{ 1}{ -1 }}\]

Answer 24

no, you are not right.

Answer 25

but "2" isnt written (dont ask me why!)