Find the average rate of change of the function over the given interval or intervals. 1) f(x)=x^3+1;
a) [2,3]
b) [-1,1]

Question

Find the average rate of change of the function over the given interval or intervals. 1) f(x)=x^3+1; 
a) [2,3] 
b) [-1,1]

anonymous · Answer

hi. do you still need some help?

anonymous · Answer

yes, I don't understand how to solve this?

anonymous · Answer

ok. this is about slope

anonymous · Answer

in other words, for the first part, you want to figure out [f(3-f(2)]/1

anonymous · Answer

this is simply rise over run in function notation of the endpoints

anonymous · Answer

this gives you the slope between the endpoints or the average rate of change

anonymous · Answer

questions are good here if you have them. :))

anonymous · Answer

I got it, I found the answer, its 19.

anonymous · Answer

that is correct.  :)

anonymous · Answer

now you can do the same thing with the second interval of [-1, 1]

anonymous · Answer

how do youfeel about this one?

anonymous · Answer

I got it, its 1

anonymous · Answer

hmmmm. i got that too.  :)) are you sure you needed help?  Nice work

anonymous · Answer

I was really confused at first, then I looked at the slope part and plugged in the numbers then I understood. LOL thanks

anonymous · Answer

my pleasure

anonymous · Answer

anything else i can help with?

anonymous · Answer

There is this other one, I am not sure about this one,
h(t)=cot t;
a.[pi/4, 3 pi/4]
b.[pi/6,pi/2]

anonymous · Answer

so what is the cot(3pi/4) and what is cot (pi/4)?  then use the same approach.

anonymous · Answer

i dont think we have to worry about cot being undefined because only sin0=0 so cot0 is undefined.  But no worries because this is not part of our interval of interest. so....

anonymous · Answer

[cot(3pi/4)-cot(pi/4)]/(3pi/-pi/4)=the average rate of change over the given interval

anonymous · Answer

does this make sense?

anonymous · Answer

oops... there should also be 4 under the 3pi in the above rate of change

anonymous · Answer

I see so I got -4/pi

anonymous · Answer

hmmmm.... so did i... are you sure you are not looking over my shoulder? lol

anonymous · Answer

lol nope, thanks again

anonymous · Answer

no problem ....do you think you have the last one?

anonymous · Answer

or would you like me to hang for security's sake?

anonymous · Answer

For the function g(x)graphed here, find the following limits or explain why they do not exist.
a.lim g(x)
x->1
b.lim g(x)
x->2
c.lim g(x)
x->3
|dw:1361485330142:dw|