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How many liters of water vapor can be produced if 13.3 liters of methane gas (CH4) are combusted, if all measurements are taken at the same temperature and pressure? Show all of the work used to solve this problem. CH4 (g) + 2 O2 (g) CO2 (g) + 2 H2O (g)
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you can make twice as many liters .. with ideal gases, the moles are proportional to the volume 1 mole = 22.414 L so you just need to use their coefficients... aA + bB -> cC moles of A/a = moles of C/c
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