In the process of developing a photographic film, silver bromide is dissolved by adding a solution of sodium thiosulphate: AgBr(s)+2NaS2O3=Na3Ag(S2O3)2(aq)+NaBr(aq) If you want to dissolve0.250g of AgBr (fw 187.8), how many milliliters of 0.0139 M Na2S2O3 should you add?
I know the right answer is 163mL. I just can't figure out how to get that answer. I'm not even getting close to the right answer.
Sorry that is 193mL NOT 163mL
since everything stoichiometrically reacts in ratios of moles, convert all the units into moles
for every mole of AgBr you need 2 of NaS... then once you know the amount of moles molarity=moles/L of solvent
Yes but I'm not getting to 193mL. Im getting really small decimal amounts
did you convert from L to millilitres?
ok I got it thank you. Its 0.250g(1/187.8g)=1.00133molAgBr x (2/1)=0.00266molNa2S2O3 0.0138M=0.0138mol/L x(1L/1000mL)=0.0000138mol/mL 0.00266/0.0000138=193mL Na2S2O3
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