Dan confirms the authenticity of an amethyst stone by a few tests. During one of the tests, he finds the angle of the refracted ray of light coming out of the amethyst into the air as 28°. If the refractive index of amethyst is 1.55, what is the incident angle?
a- 152 degree
b-26 degree
c-47 degree
d-71 degree
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OpenStudy (aaronq):
do you know what equation to use?
OpenStudy (anonymous):
no:/
OpenStudy (anonymous):
do you?
OpenStudy (aaronq):
yep, so use:
\[\eta _{1}\sin _{1} \Theta=\eta _{2}\sin \theta _{2}\]
OpenStudy (aaronq):
n is the refractive index
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OpenStudy (aaronq):
n for air is 1
OpenStudy (anonymous):
so which one would it be?
OpenStudy (aaronq):
so (1)sin(28)=(1.55)(sinx)
OpenStudy (anonymous):
it said error?
OpenStudy (anonymous):
is it 26 degrees?
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OpenStudy (aaronq):
i keep getting 17.63
OpenStudy (anonymous):
are you sure thats the right formula?
OpenStudy (aaronq):
yeah I'm pretty sure
OpenStudy (anonymous):
i dont understand
OpenStudy (aaronq):
sin28 = 0.469
0.469/1.55 = sin x
sinx= 0.3028
asin(0.3028)=x = 17.63
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OpenStudy (anonymous):
but thats none of the anwers
OpenStudy (aaronq):
idk thats what the math is saying :S
OpenStudy (aaronq):
omg I'm sorry i read it backwards
OpenStudy (aaronq):
it works out now
OpenStudy (anonymous):
so what would it be?
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OpenStudy (aaronq):
plug it into a calculator, i can't so bluntly give you the answer