Evaluate the discriminant of 3x^2+2x+1=0. Tell how many solutions the equation has and whether the solutions are real or imaginary.
A) two imaginary solutions
B) one real solution
C) two real solutions
D) cannot be determined

Question

Evaluate the discriminant of 3x^2+2x+1=0. Tell how many solutions the equation has and whether the solutions are real or imaginary.
A) two imaginary solutions
B) one real solution
C) two real solutions
D) cannot be determined

noelgreco · Answer

What do you calculate for the value of the discriminant?

campbell_st · Answer

so for a quadratic 

$$ax^2 + bx + c = 0$$

the discriminant is 

$$\Delta = b^2 - 4ac$$

so you need to calculate the discriminant 1st

campbell_st · Answer

where a = 3, b = 2 and c = 1

campbell_st · Answer

the the conditions 

$$\Delta > 0$$ unequal real roots 

    if the descriminant is a perfect square the roots are rational 

$$\Delta = 0$$

equal or repeated root. 

$$\Delta < 0$$

no real roots. Which means the roots will be a complex number.

noelgreco · Answer

Well, you were given the answer, so I can't help you try to understand the process for the future.