find all vertical and horizontal asymptotes f(x)=(3x+2)/(4x^2+2)
\[f(x)=\frac{ 3x+2 }{ 4x ^{2} +2}\]
Is there a solution to \(\large 4x^2+2=0 \) ???
4x^2=-2 x^2=-1/2 x= radical 1/2 ?
no... \(\large 4x^2+2=0 \) has no REAL solution. So your function does not have any VERTICAL asymptotes.
Vertical asymptotes: 4x^2 + 2 = 0 Here 4x^2 + 2 has no real roots but does have imaginary roots. But since we are only dealing with real numbers here, we will overlook that. And so 4x^2 + 2 has no real roots which means it is either always negative or always positive, but in this case it's always positve, i.e. 4x^2 + 2 >= 0 for all values of x. From this we can say that the rational function has no vertical asymptotes because the denominator is never equal to 0. Horizontal asymptotes: Since the degree of the denominator is higher than that of the numerator, the horizontal asymptote must be y = 0
Thank you so much! I was CLOSE! I am taking this calc course online and sometimes reading the book by myself is very challenging! I appreciate the help!
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