Question

What volume of 2.25M NaCl solution is required to react completely with 1.00L of 0.750M Pb(NO3) solution?

Pb(NO3)2(aq)+2NaCl(aq)=PbCl2(s)+2NaNO3(aq)

Answer 1

You need to find the volume of NaCl, based from formula
\[[M]=\frac{mol}{V}\]

Answer 2

They have given some values for Pb(NO3) right, so using that formula,
\[[M]=\frac{mol}{V}\]
mol=MV
n(Pb(NO3)) = (0.750)(1.00) = 0.750moles of Pb(NO3)

According to the equation,
Pb(NO3)2(aq)+2NaCl(aq)=PbCl2(s)+2NaNO3(aq)

1 Pb(NO3)2 is equivalent to 2 NaCl, so
0.750 times 2 = 1.5 moles of NaCl
then use back the equation
\[[M]=\frac{mol}{V}\]
\[V=\frac{mol}{[M]}\]
\[V=\frac{1.5}{2.25}=0.667 m^3\]

Answer 3

Ok thank you so much! You just cleared up the M to mol to V formula for me. I was getting stumped using M to get to other values. All I knew was that M=mol/L
Thank you for your help.This was the last practice problem I couldn't figure out. I might actually be ready for this quiz today now!

Answer 4

0.667 m3 is a lot!