General Solutions: Pre-calc/Trig Can someone explain the picture below? I don't understand how they went from step 3 to step 4. But I understand a general solution is y=___?___ +2pi(K)
I also know why it is x=, because we were solving for x in step 3
I don't understand how they went from step 3 to step 4. which step is that ?
Like.. I don't understand how they went from solve sinx=1/2 to x=30degrees+/- 2pi(K) How did they know that it would be 30?
In general, you use a calculator. The question is (apparently) what is the inverse sin (or arc sine) of 1/2 ? or, "what angle is it that the sin of that angle = 1/2 ?" in google's search wind, type asin(1/2) in degrees= or use a calculator. however, people memorize a few important angles: sin(0) = 0 sin(30º) = 1/2 sin(45º)= sqrt(2)/2 sin(60º) = sqrt(3)/2 sin(90º)= 1
Oh okay. When you type it into a calculator will it give you the degrees?
Oh I see now. I just had to put it in degree mode.
In the days before computers, they had tables with the values of sin , cos , tangent. now we can use a calculator. When you type it into a calculator.. Did you try?
yes, in degree mode you get degrees, radian mode, you get radians if you get weird numbers, always check your mode.
Okay, thanks :) I have a question, a specific example. Can you help me real quick?
But on a test they may expect you to memorize the angles I posted up above.
Ok , what is the question?
Write the general solution to y = arcsin (0.6428). When I put it in my calculator, I put in sin^-1(0.6438). I got roughly 40degrees. How do I find the other answer of 140? I know they are both right (40 &140) but I don't know how to find them both. Does that make sense?
yes here is a graph of sin: |dw:1361546766351:dw|
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