Suppose a bag of marbles has 4 green, 2 red, 5 yellow, 1 brown, and 7 blue marbles. What is the probability of picking a yellow marble, replacing it, and picking another yellow marble?

Question

anonymous · Answer

i got 5/19

anonymous · Answer

Plug these into your calculator 

Green- 19C4
Red- 19C2
Yellow-19C5
Brown-19C1
Blue-19C7

anonymous · Answer

You have a total of 19 marbles so all of your probabilities are out of 19. As 19 is a prime number you cannot bring any of your probabilities to lower terms.
Probability of a green selection is 4/19 , red is 2/19 , yellow is 5 /19 , brown is 1/19 , and finally blue which has the greatest probability of 7/19. 
All of these probabilities depends on the drawer of the marbles not being able to see the marbles. If you can see inside the bag then drawing the marble you want would be 100% certain lol :)

anonymous · Answer

i don't have a calculator. I can't plug it in. and so 5/19 is correct?

anonymous · Answer

yellow is 5 /19

anonymous · Answer

so yeah

kropot72 · Answer

There are 19 marbles. On the first selection the probability of picking yellow is 5/19. On the second selection the probability of picking yellow is also 5/19. The outcomes of the selections are independent of each other so the combined probability is$$P(yellow/yellow)=\frac{5}{19}\times \frac{5}{19}=you\ can\ calculate$$

anonymous · Answer

exactly