Question

Suppose that the amount of algae in a pond doubles every 4 hours. If the pond initially contains 90 pounds of algae, how much algae will be in the pond after 12 hours

Answer 1

53
zpupster






0P = Noe^(kt)
where
P is amount after doubling
No is the initial amount
.
No is 90 pounds
P is 180 pounds
t = 4 hrs
.
180= 90e^(4k)

2= e^(4k)
ln(2) = 4k
ln(2)/4 = k
0.173287 =k


F(12) = 1000e(0.173287*12)